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Originally Posted by MNBoxster
Hi,
One thing you can do is to wire a resistor into the circuit. Go to a high-end custom stereo shop (or even a Radio Shack) and get the proper resistor to drop the load into the required range. Hope this helps...
Happy Motoring!... Jim'99
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Not that simple. For example, if the load you're looking for is 4 ohms, but the speakers are going to give you a 2 ohm load, you'd need a 2 ohm resistor in series with the speakers to bring it back to 4.
However, you've just divided the power between the speakers and the resistor. In simple terms, if you had 40 watts available to drive the speakers, now you're applying 20 watts to the speaker, and 20 watts to the resistor. Fortunately, you haven't halved the sound produced by the speakers, you've reduced it by 3 - 6 dB, depending on how it's measured. You can probably adjust the fader to balance things back out.
The other problem is the resistor. I seriously doubt Radio Shack will have it, as it will have to be a Power Resistor. It will be dissipating, as heat, up to 20 watts peak in my example above. That's a pretty specialized, big, and hot resistor. A little 1/4 watt resistor from RS won't do the job.
Best thing to do is to stay within design limits and avoid bandaids like this.