Quote:
Originally Posted by Johnny Danger
I'm thinking - less draw on the electrical system means greater spark to the engine which will result in more power ?
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nope, less draw on the system = less parasitic drag from the alternator.
soooo to geek out:
Watts/745.7 (one HP) = Electrical output in HP
HP x 10% Efficiency Loss (guessing here) = HP Loss
HP + Efficiency Loss = Total HP used
so lets figure ~160 watts for the lighter
160 / 745.7 =.215
.215 X .10 = .0215
.215 + .0215 = .236hp
That blasted lighter is costing you nearly a quarter of a hp when your girl fires up a Marlboro!