Quote:
Originally Posted by Smallblock454
p1 = 10^5 Pa
V1 = 0.1m^3
T1 = 0° = 273K
V2 = 0.174m^3
T2 = 200° = 473K
p2 = ?
p2 =
p1 * V1 * T2 | 10^5 Pa * 0,1 m^3 * 473 K | 4730000 | 99574 Pa
--------------- = -------------------------------- = ---------- =
T1 * V2 | 273 K * 0,174 m^3 | 47,502 |
99574 Pa = 0,99574 Bar = 14,4 PSI
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Markus, your posts are always so exceptionally helpful, thank you for all your input on this!
14.4 psi is almost ideal for a freeze plug. Automotive cooling systems usually are designed to operate at a pressure of between 14 and 15 psi. Freeze plugs are designed to stay put and hold pressure in this application, I would assume there is a wide margin of safety, but will be testing to make sure.
I still plan to do some research to find out what the previous retrofit was that used one and what happened with peoples engines.
Silber