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Old 10-24-2007, 05:46 AM   #8
Lucky
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Join Date: Aug 2007
Location: Virginia
Posts: 244
Quote:
Originally Posted by bmussatti
Lucky, I follow your example, and would agree, but in Tholyoak's example the car is the same (without a beefed-up tranny). So he does pose an interesting question to ponder.
Guess I should read better...

Even so, I believe this is easily explained by the following High School Physics formula for the friction force observed between sliding surfaces:

F = mu * Fn

Where:
F = the force due to friction (loss in a tranny, for example)
mu = the coefficient of friction between two moving surfaces
Fn (as in "normal force") = the force applied perpendicular to the two moving surfaces

The key parameter above is "Fn", which inside a tranny occurs where gear surfaces touch and shafts push sideways against bearings (to counteract the torque that is spinning the shaft). As this "normal" force goes up, friction loss (F) goes up in a linear manner. So yes, the climbing loss as more power is put through a tranny makes perfect sense.

Yes, rotational inertia remains the same, but as friction loss climbs the inertia becomes less of a factor.
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