[Smallblock454]

OK, let's talk about the expansion of air.

And sorry i have to calculate in the metric system, because i'm too stupid to do it in the imperial system.

If we have 1 litre of air = 1000 cm3 and we heat it up 10 degree celsius it will expand 37 cm3 with every 10 degree celsius more.

So lets say the ims shaft has a volume of 1 litre (i'm retty shure it's more) and we heat it up from 0 degree celsius to 200 degree celsius as a max, value (i would say the max. should be between 120 and 150 degree celsius in the IMS area). So calculate worst case 200 degree celsius and that would mean we have an expansion of 740 cm3.

p1 = 10^5 Pa
V1 = 0.1m^3
T1 = 0° = 273K
V2 = 0.174m^3
T2 = 200° = 473K
p2 = ?

p2 =

p1 * V1 * T2 | 10^5 Pa * 0,1 m^3 * 473 K | 4730000 | 99574 Pa
--------------- = -------------------------------- = ---------- =
T1 * V2 | 273 K * 0,174 m^3 | 47,502 |

99574 Pa = 0,99574 Bar = 14,4 PSI

To compare that. The recommended 986 front tyre pressure is 2.0 Bar.

Atmospheric pressure will be set as a constant of 1 Bar at normal ground.

Additionally in a crank case we have a low pressure system. That means we have negative pressure. And that means we are below 1 Bar atmospheric pressure.

Next would be to calculate the right volume for the IMS tube so you can calculate the right pressure at a given temperature.

Personally i think that would be a lot of atmospheric pressure for a simple freeze plug in a rotating and vibrating IMS tube. Also i suspect the volume in an IMS tube is much higher. And remember the freeze plug has to stay in place and you have to prevent additional unbalancing.

Regards, Markus

PS: i don't know if there is any way to show the formula in a better way. If i open it in the editor it looks good. But if i click save it looks goofy.