Jim, good science lesson. Thanks
I have a few questions:
1) In this formula; p2 = p1 * (t2 + 459.69) / (t1 + 459.69) where does it take into account the "vessel" holding the air is rubber? Do all "vessels" follow this rule?
2) In your example about 30 psi, at 0 degrees F, then you arrive to a place that is 100 degreess F...how do you get to the tires being now 200 degrees?
3) Jim, in this example; "If you check your pressure Cold at, say 30°F and find them at 30 psi and, then again Cold at 70°F, your pressure would be 32 psi because.:
p2 = 30 * (70 + 459.69) / (30 + 459.69) = 32 psi, or a rise of 2 psi"
So if your tires we at 30 psi when it was 30 degress F outside, and then drove up to Duluth and it was -10 degrees F...the tire pressure would be 28?? My personal driving experience in the Midwest does not show this to be true. My tires would have lost more than just 2 psi!
Help me out!