At what mileage would you say the car starts to get suspension worn and other parts?

[Topless]

That depends on the car, the driver, and the weather. A Calif car lightly driven might go 150k before suspension is shot. A car driven harder or abused will wear faster. A car that is driving salted roads in winter will wear faster still.

I know, master of the obvious.

My car was a one owner Cali car that was driven regularly but lightly with dealership care and maint. At 96k we pulled the struts and they were pretty far along but still functional. My brothers car had an unknown history but appeared to have been driven much harder. At 70k his struts were completely toast. No dampening at all. I don't know how he drove it like that. How they are driven and cared for matters most.

[jcb986]

Wearing conditions depend on the driver and how he maintains his Porsche. The other and most damaging is the roads. Nice smooth roads, suspension will last a very long time, rough and bumpy roads will wear the suspension faster. Staying on top of your maintenance is the key to owning it for very long time.

[Perfectlap]

Originally Posted by Topless

That depends on the car, the driver, and the weather. A Calif car lightly driven might go 150k before suspension is shot. A car driven harder or abused will wear faster. A car that is driving salted roads in winter will wear faster still.

big time.

Me shocks were shot by 69K miles. Driven only weekends, kept in a toasty garage.
But it was driven year round in cold snowy winters, as it good for the engine (rather than letting it sit for long periods) but the tradeoff is much more abuse on the suspension/wheels. And one reason why I decided on dedicated winter wheels. I was shocked at how difficult/expensive is to replace a single Carrera factory wheel. I was being offered "bargain" prices of $500 for a used one that still needed repainting. Moral of the story, if you live in the north east have proper set ups for winter and stay on the smooth highway, avoid torn up local and city roads.